Solve the equation \(8^x-7(4)^x+14(2)^x-8=0\), where \(x\in\mathbb{R}\). vishal08052002 / September 17, 2026 ① Prove that \(u-1\) is a factor of \(u^3-7u^2+14u-8=0\).\n\n ② Solve the equation\n\[8^x-7(4)^x+14(2)^x-8=0\]\nwhere \(x\in\mathbb{R}\).